If a sphere of Tungsten weighs 12 Kg, what is it's diameter in cm ?
Thought for 9s
Approximately 10.6 cm (using the standard density of pure tungsten of 19.25 g/cm³).
seathertechnology.com
Tungsten’s density is typically given as 19.25 g/cm³ (or 19,250 kg/m³) at room temperature.
itia.info
Assuming the 12 kg refers to mass (common in such problems):Mass = 12,000 g
Volume V=mρ=12�.25�.38V = \frac{m}{\rho} = \frac{12\,000}{19.25} \approx 623.38V = \frac{m}{\rho} = \frac{12\,000}{19.25} \approx 623.38
cm³
For a sphere:
V=43πr3 ⟹ r=3V4▃.30 cmV = \frac{4}{3}\pi r^3 \implies r = \sqrt[3]{\frac{3V}{4\pi}} \approx 5.30\,\text{cm}V = \frac{4}{3}\pi r^3 \implies r = \sqrt[3]{\frac{3V}{4\pi}} \approx 5.30\,\text{cm}
d=2r.60 cmd = 2r \approx 10.60\,\text{cm}d = 2r \approx 10.60\,\text{cm}
Using 19.3 g/cm³ instead yields a nearly identical result (~10.59 cm). Real spheres may vary slightly due to purity, porosity, or temperature, but ~10.6 cm is the expected value for pure dense tungsten.
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Doubt this is true, but very French......[more]